A container with a volume of #15 L# contains a gas with a temperature of #290^o K#. If the temperature of the gas changes to #350 ^o K# without any change in pressure, what must the container's new volume be?

2 Answers

Answer:

#approx18.1L#.

Explanation:

According to ideal gas law,

#P*V=n*R*T#

Since,
#P, n, R# are constant throughout the process,

#V/T=(n*R)/P=constant#

Therefore,

#VpropT#

#V_"initial"/T_"initial"=V_"final"/T_"final"#

So,
#V_"final"=(V_"initial"*T_"final")/T_"initial"=(15*350)/290approx18.1L#

The answer is #18.1L#

May 15, 2016

Answer:

#V_2=18.1 L#

Explanation:

#P="constant"#
#V_1=15L#
#T_1=290 ^o K#

#T_2=350 ^o K#
#V_2=?#

#V_1/T_1=V_2/T_2#

#15/290=V_2/350#

#V_2=(15*350)/290#

#V_2=18.1 L#