A container with a volume of #17 L# contains a gas with a temperature of #230^o C#. If the temperature of the gas changes to #530 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-12-15T07:04:25

The new volume is #=17.9L#

We use Charles' Law

#V_1/T_1=V_2/T_2#

#V_1=17L#

#T_1=230ºC=(230+273)K=503K#

#T_2=530K#

#V_2=V_1/T_1*T_2=17/503*530=17.9L#