# A container with a volume of 17 L contains a gas with a temperature of 230^o C. If the temperature of the gas changes to 530 ^o K without any change in pressure, what must the container's new volume be?

Dec 15, 2016

The new volume is $= 17.9 L$

#### Explanation:

We use Charles' Law

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$

${V}_{1} = 17 L$

T_1=230ºC=(230+273)K=503K

${T}_{2} = 530 K$

${V}_{2} = {V}_{1} / {T}_{1} \cdot {T}_{2} = \frac{17}{503} \cdot 530 = 17.9 L$