Question

A container with a volume of `32 L` contains a gas with a temperature of `240^o K`. If the temperature of the gas changes to `160 ^o K` without any change in pressure, what must the container's new volume be?

Answer 1

New volume is `21.33L`.

Explanation:

If `P` is pressure, `V` is volume and `T` is temperature (in Kelvin), `PV/T` is constant. As pressure `P` is constant, in above case `V/T` will be constant i.e. `(V_1/T_1)=(V_2/T_2)`.

Applying this we have `32/240=V_2/160`

Hence `V_2=(32/240)*160` or #V_2=64/3) or

New volume is `21.33L`.