# A container with a volume of 35 L contains a gas with a temperature of 420^o K. If the temperature of the gas changes to 300 ^o K without any change in pressure, what must the container's new volume be?

Feb 22, 2017

The new volume is $= 25 L$

#### Explanation:

We apply Charles' Law

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$

${V}_{1} = 35 L$

${T}_{1} = 420 K$

${T}_{2} = 300 K$

${V}_{2} = {T}_{2} / {T}_{1} \cdot {V}_{1}$

$= \frac{300}{420} \cdot 35 = 25 L$