A container with a volume of #4 L# contains a gas with a temperature of #270^o K#. If the temperature of the gas changes to #120^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-03-25T10:24:18

The new volume is #=1.78L#

We apply Charles' Law

#V_1/T_1=V_2/T_2#

#V_1=4L#

#T_1=270K#

#T_2=120K#

#V_2=T_2/T_1*V_1#

#=120/270*4#

#=1.78L#