# A container with a volume of 4 L contains a gas with a temperature of 270^o K. If the temperature of the gas changes to 120^o K without any change in pressure, what must the container's new volume be?

##### 1 Answer
Mar 25, 2017

The new volume is $= 1.78 L$

#### Explanation:

We apply Charles' Law

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$

${V}_{1} = 4 L$

${T}_{1} = 270 K$

${T}_{2} = 120 K$

${V}_{2} = {T}_{2} / {T}_{1} \cdot {V}_{1}$

$= \frac{120}{270} \cdot 4$

$= 1.78 L$