A container with a volume of #4 L# contains a gas with a temperature of #770^o K#. If the temperature of the gas changes to #420^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-04-03T13:43:33

#V_2=2,18L#

#"given data:"#

#V_1=4L#
#T_1=770^o K#
#T_2=420^o K#
#V_2=?#

#"solution:"#
#V_1/T_1=V_2/T_2#

#4/770=V_2/420#

#V_2=(4*420)/770#

#V_2=2,18L#