A container with a volume of 48 L contains a gas with a temperature of 140 K. If the temperature of the gas changes to 90 K without any change in pressure, what must the container's new volume be?

1 Answer
Feb 20, 2016

Using the Combined Gas Law, $\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$, but leaving out pressure because it remains constant, ${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2} \to {V}_{2} = \frac{{V}_{1} {T}_{2}}{T} _ 1 = \frac{48 \cdot 90}{140} = 30.9$ $L$.