A container with a volume of #6 L# contains a gas with a temperature of #150^o K#. If the temperature of the gas changes to #120 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2017-07-04T05:23:55

The volume is #=4.8L#

We apply Charles' Law

#V_1/T_1=V_2/T_2#

The initial volume is #=6L#

The initial temperature is #T_1=150K#

The final temperature is #T_2=120K#

The final volume is

#V_2=T_2/T_1*V_1=120/150*6#

#=4.8L#