# A container with a volume of 6 L contains a gas with a temperature of 150^o K. If the temperature of the gas changes to 120 ^o K without any change in pressure, what must the container's new volume be?

##### 1 Answer
Jul 4, 2017

The volume is $= 4.8 L$

#### Explanation:

We apply Charles' Law

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$

The initial volume is $= 6 L$

The initial temperature is ${T}_{1} = 150 K$

The final temperature is ${T}_{2} = 120 K$

The final volume is

${V}_{2} = {T}_{2} / {T}_{1} \cdot {V}_{1} = \frac{120}{150} \cdot 6$

$= 4.8 L$