# A container with a volume of 6 L contains a gas with a temperature of 250^o K. If the temperature of the gas changes to 350 ^o K without any change in pressure, what must the container's new volume be?

Jun 28, 2016

$\text{The new volume is:}$
${V}_{f} = 8.4 L$

#### Explanation:

${V}_{i} = 6 L \text{ ; The initial volume of gas}$
${T}_{i} = {250}^{o} K \text{ ; The initial temperature of gas}$

${T}_{f} = {350}^{o} K \text{ ; The final temperature of gas}$
V_f=?" ; The final Volume of gas"

${V}_{i} / {T}_{i} = {V}_{f} / {T}_{f}$

$\frac{6}{250} = {V}_{f} / 350$

${V}_{f} = \frac{6 \cdot 350}{250}$

${V}_{f} = 8.4 L$