# A container with a volume of 6 L contains a gas with a temperature of 420^o K. If the temperature of the gas changes to 370 ^o K without any change in pressure, what must the container's new volume be?

Apr 19, 2018

The new volume is $= 5.29 L$

#### Explanation:

Apply Charles' Law

$\text{ Volume "/" Temperature " = "Constant}$

$\text{At constant pressure}$

${V}_{1} / {T}_{1} = {V}_{2} / {T}_{2}$

The initial volume is ${V}_{1} = 6 L$

The initial temperature is ${T}_{1} = 420 K$

The final tempertaure is ${T}_{2} = 370 K$

The final volume is

${V}_{2} = {T}_{2} / {T}_{1} \cdot {V}_{1} = \frac{370}{420} \cdot 6 = 5.29 L$