A container with a volume of #7 L# contains a gas with a temperature of #420^o C#. If the temperature of the gas changes to #570 ^o K# without any change in pressure, what must the container's new volume be?
The new volume is
Let's start off with identifying our known and unknown variables:
- Initial Volume
- Initial Temperature
- Final Temperature
- Final Volume
The equation we use is
where the numbers
I must also add that the volume must have units of liters and the temperature must have units of Kelvin. In our case the volume is fine, we just have to change the first temperature from centigrade to Kelvins.
We do this by adding
#"273.15K" + 420^@"C" = "693.15K"#
Now we just rearrange the equation and plug and chug.
#V_2 = (T_2 * V_1)/(T_1)#
#V_2 = (570cancel("K") * "7L") / (693.15 cancel("K"))#
#V_2 = "5.76 L"#