A container with a volume of #7 L# contains a gas with a temperature of #420^o K#. If the temperature of the gas changes to #360 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2018-05-20T05:07:36

#6 L#

Given: constant pressure, volume of a gas = #7 L; " "T = 420 K#. Temperature changes to #360 K#, what is the new volume?

The general gas law: #(P_1V_1)/T_1 = (P_2V_2)/T_2# where Temperature is required to be in the units of Kelvin.

When the pressure is constant, we can use Charles' Law:

#V_1/T_1 = V_2/T_2#

Solve for #" "V_2: " "(7)/420 = V_2/360#

Use the cross-product to solve #a/b = c/d; " "a*d = b*c#

#420V_2 = 7*360 = 2520#

#(420V_2)/420 = 2520/420 = 6#

#V_2 = 6 L#