A container with a volume of #8 L# contains a gas with a temperature of #270^o C#. If the temperature of the gas changes to #360 ^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-05-11T20:43:04

#V_2=5.30L#

#V_1=8L#
#T_1=270 ^o C=270+273=543 ^o K#

#T_2=360 ^o K#
#V_2=?#

#V_1/T_1=V_2/T_2#

#8/543=V_2/360#

#V_2=(8*360)/543#

#V_2=5.30L#