A crane lifts a 487 kg beam vertically at a constant velocity. If the crane does 5.20 x 10^4 of work on the beam find the vertical distance that it lifted the beam?

I understand the equation that needs to be used to solve the problem. What don't I understand is how does the coefficient of gravity(g) which is 9.8m/s plays a role in this question. Can someone kindly explain this part for me?

1 Answer

Answer:

Vertical distance #d=10.9" "#meters

Explanation:

The only force involve in the crane is the weight #F# of the beam

The force of the weight
#F=mg#

#F=487" "##kg*(-9.8" "m/sec^2")#

#F=-4772.6" "#Newtons (negative because weight is downward direction)

Force of the crane is equal to weight directed upward (positive)#=+4772.6" "#Newtons

The work #W=F*d" "#where #d=#distance

#d=W/F=(5.2 x 10^4)/4772.6#

#d=10.89552864" "#meters

God bless....I hope the explanation is useful.