A ferris wheel has a diameter of approximately 50 meters. The wheel rotates once every 6 minutes. Find the linear speed at the outer edge of the ferris wheel in meters per hour?

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Answer 1 · 2018-03-22T03:32:19

#"Linear speed of the outer edge of the ferris wheel is "#

# color(blue)(= 1570.8 " meters per hour ") or ~~ 1.57 " kmph"#

Given #"diameter of the wheel "= 50 " " m#

#"Circumference of the wheel " c = pi d " " m = 50 pi " m"##

#"speed of rotation of the wheel " s = 6 " " m " per revolution"#

#"Distance travelled by the wheel in one revolution in 6 minutes " c = 50 pi" m"#

#"Speed of the ferris wheel " = (50 pi )/ 6 " m per min"#

#"Speed of wheel in one hour" = ((50 pi )/ cancel6) *cancel(60)^color(red)(10)" m per hr"#

#=> 50 pi * 10 = 500 pi = 1570.8 " meters per hour"#