# A flask contains 85.5 g C_12H_22O_11 (sucrose) in 1.00 liters of solution. What is the molarity?

Jul 16, 2017

$\text{molarity} = 0.250 M$

#### Explanation:

We're asked to find the molar concentration (molarity) of a sucrose solution, given the volume of solution and mass of solute.

The equation for molarity is

$\text{molarity" = "mol solute"/"L soln}$

We're given the volume is $1.00$ $\text{L}$, so we just need to find the moles of solute (we're given grams) via the molar mass of sucrose ($342.30$ $\text{g/mol}$):

85.5cancel("g sucrose")((1color(white)(l)"mol sucrose")/(342.30cancel("g sucrose"))) = color(red)(0.250 color(red)("mol sucrose"

Therefore, we have

"molarity" = (color(red)(0.250color(white)(l)"mol sucrose"))/(1.00color(white)(l)"L soln") = color(blue)(0.250M