A force of 24 Newtons is applied to the small piston of a hydraulic lift. If the piston has a diameter of 20 cm, determine the pressure (in kPa) that would be created in the hydraulic fluid?

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Answer 1 · 2018-01-10T08:40:26

0.76 kPa

Pressure = Force / Area

The area is given by:

#sf(A=pir^2)#

r = 20/2 = 10 cm = 0.1 m

#:.##sf(A=pixx0.1^2=0.01picolor(white)(x)m^2)#

#sf(P=F/A=24/(0.01pi)=763.8color(white)(x)"N""/"m^2"=763.8color(white)(x)Pa)#

#sf(P=0.76color(white)(x)kPa)#