A function #h# is defined by #h(x) = x^2+2#, what is #h(4x)#?
1 Answer
May 21, 2017
Explanation:
#"to evaluate " h(4x)" substitute " x=4x" into " h(x)#
#rArrh(color(red)(4x))=(color(red)(4x))^2+2#
#color(white)(rArrh(4x))=16x^2+2#
