# A gas at 155 kPa and 25'C has an initial volume of 1.00 L. The pressure of the gas increases to 605 kPa as the temperature is raised to 125°C. What is the new volume?

Jan 21, 2018

${V}_{2} = 0.342 \cdot L$...the gas is compressed....

#### Explanation:

We use the old $\text{combined gas law...}$

$\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$

And if we solve for ${V}_{2} = \frac{{P}_{1} {V}_{1}}{T} _ 1 \times {T}_{2} / {P}_{2}$...the which product CLEARLY has the units of $\text{volume}$. And we plug in the values....

${V}_{2} = \frac{155 \cdot \cancel{k P a} \times 1.00 \cdot L \times 398 \cdot \cancel{K}}{298 \cdot \cancel{K} \times 605 \cdot \cancel{k P a}} = 0.342 \cdot L$

Pressure wins here over temperature....