# A gas at standard temperature (0°C) has a volume of 30.50 Liters and a pressure of 931 torr.What is the volume at standard pressure ?

Jul 17, 2018

The final volume will be $\text{37.9 L}$.

#### Explanation:

Standard temperature for gas laws is $\text{273.15 K}$, and standard pressure is $\text{100 kPa}$.

Since the temperature remains constant, we can drop it as a variable. We would then have two variables, volume and pressure. Boyle's law describes the relationship between volume and pressure of a gas, which states that the pressure and volume of a gas are inversely proportional. This means that if the pressure increases, the volume decreases, and vice versa. The formula for Boyle's law is:

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

Known

P_1=931color(red)cancel(color(black)("torr"))xx("1 kPa")/(7.500638color(red)cancel(color(black)("torr")))="124.12 kPa"
${V}_{1} = \text{30.50 L}$

${P}_{2} = \text{100 kPa}$

Unknown

${V}_{2}$

Solution

Rearrange the equation to isolate ${V}_{2}$, plug in the known values and solve.

${V}_{2} = \frac{{P}_{1} {V}_{1}}{{P}_{2}}$

V_2=(124.12color(red)cancel(color(black)("kPa"))xx30.50"L")/(100color(red)cancel(color(black)("kPa")))="37.9 L" (rounded to three significant figures)