A gas occupies 11.2 liters at 0.860 atm. What is the pressure if the volume becomes 15.0 L?

1 Answer
Manish Bhardwaj
Jul 2, 2014

Boyle studied the relationship between the pressure of a trapped gas and its volume. The data obtained by him shows that the product of pressure and volume for the trapped air sample is constant at a constant temperature.

if volume of the gas increases, its pressure decreases, and vice versa. mathematically, if the volume of the gas is #V_1# and its pressure is #P_1#. Let us suppose that its volume has been increased to #V_2#, the as per the Boyle's law its pressure will decrease and let us assume the new pressure is #P_2#.

#P_1# #V_1# =#P_2##V_2#

#P_1# = 0.860 atm
#V_1# = 11.2 L
#P_2# = ?
#V_2#= 15 L substitute the values;

0.860 atm x 11.2 L = #P_2# x 15 L

#P_2# = 0.860 atm x 11.2 L / 15 L

#P_2# = 9.632 atm L / 15 L = 0.642 atm

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