# A gas occupies a volume of 0.6 L at 10.1 kPa. What volume will the gas occupy at 101 kPa?

Feb 29, 2016

$\text{.06 L}$

#### Explanation:

Use the equation for Boyle's Law

${P}_{1} {V}_{1} = {P}_{2} {V}_{2}$

Plug in your values to get

$\left(\text{10.1 kPa") xx (".6 L") = ("101 kPa}\right) \times {V}_{2}$

[(10.1cancel("kPa"))(".6 L")]/(101cancel("kPa"))= V_2

${V}_{2} = \text{.06 L}$