# A gas tank has a volume of 28.1m^3 and a pressure of 18.4atm. The temperature of the gas is 32ºC. What is the Celsius temperature if the pressure changes to 22.7 atm?

## Whats the gas law, and formula? And also how do i solve this?

May 3, 2018

$\text{39.5°C}$

#### Explanation:

The Combined Gas Law states that $\frac{{P}_{1} {V}_{1}}{T} _ 1 = \frac{{P}_{2} {V}_{2}}{T} _ 2$.

$P$ = Pressure
$V$ = Volume
$T$ = Temperature

Since we're using a gas tank and it isn't specified, I'm going to assume the Volume remains constant, so we can eliminate the Vs, giving us ${P}_{1} / {T}_{1} = {P}_{2} / {T}_{2}$.

Plugging in values:

$\frac{\text{18.4atm"/"32°C" = "22.7atm}}{T} _ 2$

We need to isolate the ${T}_{2}$, so we'll cross multiply and isolate the value.

${T}_{2} \text{18.4atm" = "22.7 atm * 32°C}$

T_2 = ("22.7 atm * 32°C")/"18.4atm"

Now let's simplify the equation. Our atm's cancel, giving us:

T_2 = ("22.7 * 32°C")/"18.4"

After calculating the values and applying sig figs (3 sig figs), we are given $\text{39.5°C}$