A gas with a volume of 4.0 L at a pressure of 205 kPa is allowed to expand to a volume of 12.0 L. What is the pressure in the container if the temperature remains constant?

1 Answer
Apr 1, 2017

Answer:

We use old #"Boyle's Law"#, #PV=k,# where #k# is a #"constant"#.

Explanation:

And the utility of this law means that we could use non-standard units, if our units are consistent.

Given that #PV=k,# (temperature constant), it follows that...........

#P_1V_1=P_2V_2#..........

We solve for #P_2=(P_1V_1)/(V_2)=(205*kPaxx4.0*cancelL)/(12.0*cancelL)#

#~=68*kPa#

The pressure has reasonably decreased............Why #"reasonably?"# And given consistent units, I could use #"pints"#, #"foot lbs"#, #"atmospheres"# whatever...........