A golf ball at rest is dropped from the top of a building. What is the velocity of the ball after 3 s?

1 Answer
Mar 12, 2018

I think it'll be #29.4 \ "m/s"^2#, neglecting air resistance.

Explanation:

Well, if no other forces are acting on the ball, then its velocity will just be the acceleration of gravity, increasing each time.

The acceleration of gravity is approximately #9.8 \ "m/s"^2#.

So, at

#t=1 \ "s", v=9.8 \ "m/s"#

#t=2 \ "s",v=9.8*2=19.6 \ "m/s"#

#t=3 \ "s", v=9.8*3=29.4 \ "m/s"#