A golf ball is hit in the air with an upward velocity of 45ft from the top of a building of 50ft.(t)=16t^2+45+50 Round to the nearest tenth?

How long will it take for the golfball to reach its max height? How far above the ground will the golfball be at its max height?

1 Answer
Apr 30, 2018

Given,

#nu_0 = (45"ft")/"s" * (0.3048"m")/"ft" approx (13.7"m")/"s"#

#nu = 0# (at the projectile's maxima)

#a = g#

We will approximate this as one dimensional motion due to your lack of data. We'd need an angle to move forward with parabolic motion.

Recall,

#nu = nu_0 + at#, and

#nu^2 = nu_0^2 + 2aDeltax#

Hence, it will take,

#=> t = (Deltanu)/g approx 1.4"s"#

to reach its maximum height, which happens to be,

#=> Deltax = (nu^2-nu_0^2)/(2a) approx 25"m"#

when considering its starting height of #50"ft"#.