# A heater is marked 50 watts will evaporate at 0.05kg of boiling water find the specific latent heat of vaporization of the water?

## This is a heat energy question it is under specifi latent heat of vaporization. I don't know how to solve it Please help me

The formula is $L = \frac{Q}{m}$ , where L is the latent heat, Q is the change in energy in terms of heat, and m is the substance's mass.
$L = \frac{50}{0.05}$