Question

A hemispherical tank is filled with water and has a diameter of 10 feet. If water weighs 62.4 pounds per cubic foot what is the total weight of the water in a full tank to the nearest pound ?

Answer 1

I tried this:

Explanation:

We know that the volume of a sphere is:

`V=4/3pir^3`
where `r=10/2=5"ft"` is the radius;

we need half of this, so we use:

`V/2=2/3pir^3=261.8"ft"^3`

giving a total weight of water of:

`W=261.8*62.4=16,336` pounds