A hot-air balloon is rising straight up with a speed of 3.8 m/s. A ballast bag is released from rest relative to the balloon at 9 m above the ground. How much time elapses before the ballast bag hits the ground?

A hot-air balloon is rising straight up with a speed of 3.8 m/s. A ballast bag is released from rest relative to the balloon at 9 m above the ground. How much time elapses before the ballast bag hits the ground?

___ s

1 Answer
Jane
Jan 31, 2018

As,the hot air ballon is rising up with a constant velocity of #3.8 m/s#,so when the bag will be relesead #9 m# above the ground it will have an initial velocity upwards and the magnitude will be the same as that of the hot air ballon has. Then it will come down due to gravitational force.

So,we can apply #s=ut+1/2 g t^2# (here, #t# is the time after which the bag will come back to the ground)

where, #s=9,u=-3.8,g=10#

so, #t=1.77 s#

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