A is the translation expressed by matrix[3_4]. B is the translation expressed by matrix[-2_1]. And P is the point (-1, -2). Thus: (B○A○B○A○B)(P)= ?

1 Answer
Oct 23, 2017

#(BcircAcircBcircAcircB)(P)=(72,-32)#
#color(white)("XXXXXXXXXXXXXXXXXXXXXXXX")#(see note below)

Explanation:

I am unfamiliar with this notation but I have assumed that
#[3"_"4]# is equivalent to the scaling matrix: #[(3,0),(0,4)]#

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#BcircP=B(P)=[(-1,-2)]xx[(-2,0),(0,1)]#
#color(white)("XXX")=[((-1)xx(-2)+(-2)xx0,color(white)("xxx")(-1)xx0,(-2)xx1)]#

#color(white)("XXX")=[(2,-2)]#

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Similarly:
#AcircBcircP=A(B(P))=[(2,-2)]xx[(3,0),(0,4)]#

#color(white)("XXX")=[(6,-8)]#

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

#BcircAcircBcircP=[(6,-8)]xx[(-2,0),(0,1)]#

#color(white)("XXX")=[(-12,-8)]#

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

#AcircBcircAcircBcirP=[(-12,-8)]xx[(3,0),(0,4)]#

#color(white)("XXX")=[(-36,-32)]#

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

#BcircAcircBcircAcircBcircP=[(-36,-32)]xx[(-2,0),(0,1)]#

#color(white)("XXX")=[(72,-32)]#