A lizard accelerates from 2.5 m/s to 10.8 m/s in 4 seconds what is the lizards average acceleration?

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Answer 1 · 2018-04-10T10:04:25

#"2.075 m/s"^2#

Acceleration: the rate of change of velocity per unit of time.

#"Acceleration" = (v - u)/t = "10.8 m/s - 2.5 m/s"/"4 s" = "2.075 m/s"^2#

Answer 2 · 2018-04-10T12:49:24

#2.075 \ "m/s"^2#

Acceleration is defined through the equation,

#a=(dv)/dt#

#(dv)/dt# is the change of velocity respect to time

For a simple problem like this, no need for differential calculus :), we can use a simple formula like:

#a=(v-u)/t#

#v# is the final velocity

#u# is the initial velocity

#t# is the time

And so, we get,

#a=(10.8 \ "m/s"-2.5 \ "m/s")/(4 \ "s")#

#=(8.3 \ "m""/"color(red)cancelcolor(black)"s")/(4color(red)cancelcolor(black)"s")#

#=2.075 \ "m/s"^2#