# A lunch pail is accidentally kicked off a steel beam on a building under construction. Suppose the initial horizontal speed is 1.50 m/s. How far does the lunch pail fall after it travels 3.50 m horizontally?

Nov 26, 2015

$26.7 \text{m}$

#### Explanation:

The horizontal component of the velocity is constant so we can get the time of flight from:

$v = \frac{s}{t}$

$\therefore t = \frac{s}{v} = \frac{3.5}{1.5} = 2.33 \text{s}$

Now we can consider its vertical motion:

$s = \frac{1}{2} \text{g} {t}^{2}$

$\therefore s = \frac{1}{2} \times 9.8 \times {2.33}^{2} = 26.7 \text{m}$