# A machine shop worker records the mass aluminum as 176 g. If one side of the cube measures 4 cm, what is the density of the aluminum?

$\text{Density}$ $=$ $\text{Mass"/"Volume}$, so...........
${\rho}_{\text{Aluminum}}$ $=$ $\frac{176 \cdot g}{4 \cdot c m} ^ 3$ $=$ $2.76 \cdot g \cdot c {m}^{-} 3$.