A man heats a balloon in the oven. If the balloon initially has a volume of 4 liters and a temperature of 20°C, what will the volume of the balloon be after he heats it to a temperature of 250°C?

1 Answer
Jun 25, 2016

Answer:

We use old Charles' Law. to get approximately #7 "L"#.

Explanation:

Since, for a given quantity of gas, #VpropT# if #P# is constant, #V=kT#.

Solving for #k#, #V_1/T_1=V_2/T_2#, and #V_2=(V_1xxT_2)/T_1#; #T# is reported in #"degrees Kelvin"#, #V# may be in whatever units you like, #"pints, sydharbs, gills, bushels etc."#. Of course, we stick with sensible units, i.e. #L," litres"#.

Thus #V_2# #=# #(4 "L"xx(250+273)K)/((20+273)K)# #~=##7 "L"#