# A mass of 134 g of manganese dibromide is dissolved in 225 g of water. What is the molality of the solution?

$\text{Molality} \cong 2.8 \cdot m o l \cdot k {g}^{-} 1$
By definition, $\text{molality"="moles of solute"/"kilograms of solvent}$, and thus for this scenario, we work out the quotient,
"Molality"=((134*g)/(214.75*g*mol^-1))/(225*gxx10^-3*kg*g^-1)=??*mol*kg^-1