Question

A mass of 134 g of manganese dibromide is dissolved in 225 g of water. What is the molality of the solution?

Answer 1

`"Molality"~=2.8*mol*kg^-1`

Explanation:

By definition, `"molality"="moles of solute"/"kilograms of solvent"`, and thus for this scenario, we work out the quotient,

`"Molality"=((134*g)/(214.75*g*mol^-1))/(225*gxx10^-3*kg*g^-1)=??*mol*kg^-1`