A mixture of He, Ne and Ar has a pressure of 7.85 atm. If the Ne has a mole fraction of 0.47 and Ar has a mole fraction of 0.23, what is the pressure of He? A) 4.2atm B) 3.7 atm C )1.8 atm D) 5.5 atm E 2.4 atm

Question

13212 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-27T07:39:53

#"Option E"#

You got a three component mix....the sum of the molar fractions MUST add up to ONE....

And so #chi_(He)=1-chi_(Ne)-chi_(Ar)=1-0.47-0.23=0.30#...

And since the mole fraction is directly proportional to the total pressure....

#P_(He)=chi_(O_2)xxP_"total"=0.30xx7.85*atm-=2.355*atm#...