# A model train, with a mass of 12 kg, is moving on a circular track with a radius of 3 m. If the train's rate of revolution changes from 6 Hz to 1 Hz, by how much will the centripetal force applied by the tracks change by?

Jul 15, 2017

The centripetal force changes by $= 35.531 k N$

#### Explanation:

The centripetal force is

$F = m r {\omega}^{2}$

The mass is $m = 12 k g$

The radius $r = 3 m$

The change in angular velocity is

$\Delta \omega = \left(6 - 1\right) \cdot 2 \pi = \left(10 \pi\right) r a {\mathrm{ds}}^{-} 1$

The variation in centripetal force is

$\Delta F = m r {\left(\Delta \omega\right)}^{2}$

$= 12 \cdot 3 \cdot {\left(10 \pi\right)}^{2}$

$= 35531 N$