A model train with a mass of #2 kg# is moving along a track at #9 (cm)/s#. If the curvature of the track changes from a radius of #6 cm# to #3 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Jun 18, 2017

Answer:

The centripetal force changes by #=0.27N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

mass, #m=2kg#

speed, #v=0.09ms^-1#

radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=2*0.09^2/0.06=0.27N#

#F_2=mv^2/r_2=2*0.09^2/0.03=0.54N#

#DeltaF=0.54-0.27=0.27N#