A model train with a mass of #3 kg# is moving along a track at #12 (cm)/s#. If the curvature of the track changes from a radius of #4 cm# to #8 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Mar 9, 2018

Answer:

The change in centripetal force is #=0.54N#

Explanation:

The centripetal force is

#vecF_C=(mv^2)/r*vecr#

The mass is of the train #m=3kg#

The velocity of the train is #v=0.12ms^-1#

The radii of the tracks are

#r_1=0.04m#

and

#r_2=0.08m#

The variation in the centripetal force is

#DeltaF=F_2-F_1#

The centripetal forces are

#||F_1||=3*0.12^2/0.04=1.08N#

#||F_2||=3*0.12^2/0.08=0.54N#

#DeltaF=F_1-F_2=1.08-0.54=0.54N#