A model train with a mass of #3 kg# is moving along a track at #16 (cm)/s#. If the curvature of the track changes from a radius of #15 cm# to #18 cm#, by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-02-11T07:04:09

The answer is #=2.56N#

The centripetal force is

#F=(mv^2)/r#

The variation in centripetal force is

#DeltaF=(mv^2)/(Delta r)#

#=(3*(0.16)^2)/(0.18-0.15)#

#=(3*0.16*0.16)/0.03#

#=2.56N#