A model train with a mass of #3 kg# is moving along a track at #16 (cm)/s#. If the curvature of the track changes from a radius of #12 cm# to #32 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
May 5, 2017

Answer:

The change in centripetal force is #=0.4N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

mass, #m=3kg#

speed, #v=0.16ms^-1#

radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=3*0.16^2/0.12=0.64N#

#F_2=mv^2/r_2=3*0.16^2/0.32=0.24N#

#DeltaF=0.64-0.24=0.4N#