A model train, with a mass of #3 kg#, is moving on a circular track with a radius of #8 m#. If the train's rate of revolution changes from #1/4 Hz# to #3/8 Hz#, by how much will the centripetal force applied by the tracks change by?

Question

1230 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-08T05:29:48

The centripetal force changes by #=14.8N#

The centripetal force is

#F=mr omega^2#

mass is #m=3kg#

radius #r=8m#

#Delta omega=(3/8-1/4)*2pi=(1/4pi)rads^-1#

The variation in centripetal force is

#DeltaF=mr(Delta omega)^2#

#=3*8*(1/4pi)^2#

#=14.8N#