A model train with a mass of #4 kg# is moving along a track at #9 (cm)/s#. If the curvature of the track changes from a radius of #180 cm# to #63 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Feb 14, 2017

Answer:

The centripetal force changes by #0.028N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

The change in centripetal force is

#DeltaF=(mv^2)/(Delta r)#

So,

#DeltaF=(4*0.09^2)/(1.8-0.63)=0.0324/1.17N#

#=0.028N#