A model train with a mass of #4 kg# is moving along a track at #9 (cm)/s#. If the curvature of the track changes from a radius of #180 cm# to #24 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Jul 29, 2017

Answer:

The change in centripetal force is #=0.177N#

Explanation:

The centripetal force is

#F=(mv^2)/r#

mass, #m=(4)kg#

speed, #v=(0.09)ms^-1#

radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=4*0.09^2/1.8=0.018N#

#F_2=mv^2/r_2=4*0.09^2/0.24=0.135N#

#DeltaF=0.135-0.018=0.177N#