A model train with a mass of #4 kg# is moving along a track at #9 (cm)/s#. If the curvature of the track changes from a radius of #36 cm# to #24 cm#, by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-10-14T08:23:40

The change in centripetal force is #=0.045N#

The centripetal force is

#F=(mv^2)/r#

The mass, #m=(4)kg#

The speed, #v=(0.09)ms^-1#

The radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=4*0.09^2/0.36=0.09N#

#F_2=mv^2/r_2=4*0.09^2/0.24=0.135N#

#DeltaF=0.135-0.09=0.045N#