A model train with a mass of #5 kg# is moving along a track at #12 (cm)/s#. If the curvature of the track changes from a radius of #32 cm# to #24 cm#, by how much must the centripetal force applied by the tracks change?

Question

1127 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-09-27T05:33:51

The change in centripetal force is #=0.075N#

The centripetal force is

#F=(mv^2)/r#

The mass, #m=(5)kg#

The speed, #v=(0.12)ms^-1#

The radius, #=(r) m#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=mv^2/r_1=5*0.12^2/0.32=0.225N#

#F_2=mv^2/r_2=5*0.12^2/0.24=0.3N#

#DeltaF=0.3-0.225=0.075N#