A model train with a mass of #5 kg# is moving along a track at #14 (cm)/s#. If the curvature of the track changes from a radius of #4 cm# to #24 cm#, by how much must the centripetal force applied by the tracks change?

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Answer 1 · 2017-03-06T17:54:45

The change in centripetal force is #=2.04N#

The centripetal force is

#F=(mv^2)/r#

#m=mass=5kg#

#v=0.14ms^-1#

The variation in centripetal force is

#DeltaF=F_2-F_1#

#F_1=5*0.14^2/0.04=2.45N#

#F_2=5*0.14^2/0.24=0.41N#

#DeltaF=2.45-0.41=2.04N#