A model train with a mass of 5 kg is moving along a track at 16 (cm)/s. If the curvature of the track changes from a radius of 88 cm to 28 cm, by how much must the centripetal force applied by the tracks change?

Feb 9, 2018

The $\Delta F = 0.3117$

Explanation:

Assuming constant velocity and mass.

$\Delta F = {F}_{2} - {F}_{1}$
The change in force is equivalent to the force being applied currently subtracted from the force that will be applied.

Physics is always in Kilograms, Meters, and Seconds . So convert.

${F}_{\text{Centripital}} = \frac{\left(m a s s\right) \cdot {\left(v e l o c i t y\right)}^{2}}{r a \mathrm{di} u s}$

Use the equation to plug into our formula for $\Delta F$

$\Delta F = \frac{\left({m}_{2}\right) \cdot {\left({v}_{2}\right)}^{2}}{{r}_{2}} - \frac{\left({m}_{1}\right) \cdot {\left({v}_{1}\right)}^{2}}{{r}_{1}}$

$\Delta F = \frac{\left(5\right) \cdot {\left(0.16\right)}^{2}}{0.28} - \frac{\left(5\right) \cdot {\left(0.16\right)}^{2}}{0.88}$