A model train with a mass of #7 kg# is moving along a track at #12 (cm)/s#. If the curvature of the track changes from a radius of #32 cm# to #36 cm#, by how much must the centripetal force applied by the tracks change?

1 Answer
Mar 25, 2018

Answer:

The change in centripetal force is #=0.035N#

Explanation:

The centripetal force is

#vecF_C=(mv^2)/r*vecr#

The mass is of the train #m=7kg#

The velocity of the train is #v=0.12ms^-1#

The radii of the tracks are

#r_1=0.32m#

and

#r_2=0.36m#

The variation in the centripetal force is

#DeltaF=F_2-F_1#

The centripetal forces are

#||F_1||=7*0.12^2/0.32=0.315N#

#||F_2||=7*0.12^2/0.36=0.280N#

#DeltaF=F_1-F_2=0.315-0.280=0.035N#